0-9 digits how many four digit combinations can you have?

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10,000, if it is possible to have all digits the same (0000). 9,991 if not (0001)
If all digits must be different (0123), then 5,040
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How many combinations can you make using four digits?

1234567890 Those are all the digits that exist. So, since there are 10 kinds of digits and four available spots, you must 10 4 . 10 times 10 times 10 times 10 = 10,000. There are 10,000 different combinations. The last person was too vague. I deleted his answer. Or, you can see tha (MORE)

Numbers 0-9 how many different 13 digit combination can be made?

10,000,000,000,000. This would be the number of permutations on a 13-position combination lock, for example.. In the first position there would be one number out of ten possibilities (0-9).. Next to any one number there would be any one of ten again. So in the first two positions there are 10 x 1 (MORE)

If you have 9 numbers how many different 6 digit combinations?

We treat this as a permutations and combinations problem... as there are two possible 'rules' involved. If we are allowed to repeat a digit (such as 456537 - which as two 5s in it) then there are 9 options for every digit. So 9 x 9 x 9 x 9 x 9 x 9 = 531441 different six-digit numbers from a c (MORE)

What are the four digit combinations for 0-9?

If you don't mind starting off with one or more zeros, then they are every number from 0000 to 9999. That's 10,000 of them. If a number can't start with zeros, then it's every number from 1000 to 9999. That's the same 10,000 with the first 1,000 discarded ... total of 9,000 left.

How many combinations of the numbers 1 and 4 can there be using four digits?

Think of either using or not using the numbers 1 and 4 for each digit.. For example, let ____ ____ _____ ____ be the 4 digit number, now 1 can either go in to the first spot or 4 can. So there are 2 choices for that spot, and similarly two for the next spot and the next and the last. So there are 2 (MORE)

How many combinations of 9 digit numbers can be produced from the numbers 0 through 9?

If all numbers can be used as many times as wanted then there are 10 9 = one billion combinations. If each number can be used only once, there are 10!/(10-9)! = 10!/1! = 10! = 3628800 combinations. * * * * * Clearly answered by someone who does not know the difference between PERMUTATIONS and (MORE)

How many combinations of three digits can be made from the numbers 0-9?

The question does NOT say that the three places must be differentdigits, so repetition is allowed. The first digit can't be zero, sothere are 9 choices for it. The second digit can be any one of the 10, including zero. The third digit can also be any one of the 10, including zero. Sothe quantity of (MORE)

List of four digit combinations of 0123456789?

The list is so easy to construct that you can even do it yourself. Here's how: -- Begin with the number 1,000. -- Count from 1,000 to 9,999. -- Write down every number you say. There's your list.

How many 3 digit combinations can be made from 0 to 9 digits?

Assuming the digits can be used again, there are 10*10*10 or 1000 three digit combinations. IF YOUR LOOKING FOR 3 DIGIT LOTTERY ANSWERS HERE THEY ARE! Of the 1000 3-digit numbers 720 are non-repeating, 270 one-repeating, and 10 triples. Since a non-repeating number has 5 more siblings, we can divi (MORE)

How many combinations of 9 digits are possible if no two adjacent digits are the same?

The first can be any one of 10 digits. For each of those . . . The second can be any one of the nine digits not the same as the first. For each of those . . . The third can be any one of the nine digits not the same as the second. For each of those . . . The fourth can be any one of the nine d (MORE)

How many 4 digit combinations can be made with 5 digits?

If no digit can be repeated then there are 5 combinations, abcd, abce, abde, acde and bcde. If you regard abdc as different from abcd then each of the 5 basic sets could be arranged 24 ways and the total would be 120 combinations.

How many 3 digit combinations can be made from 0 to 9 digits not repeating?

The correct answer is 720. This is obtained by multiplying the binomial coefficients C(10,1), C(9,1) and C(8,1). However, if you would not like the first digit to be a zero, then the answer changes slightly. There are now 648 solutions. This is found by counting all 3 digit combinations in which zer (MORE)

How many different 3 digit combinations can there be if the digits are distinct?

With 3 digit numbers there are 10 digits (0, 1, ..., 9) from which to select 3 different digits. This can be done in: 10 C 3 = 10! / (10-3)!3! = 120 ways. . For a set with n items, r of them can be selected (permuted) in: n x (n-1) x ... x (n - (r +1)) = n! / (n-r)! = n P r . ways. Howe (MORE)

How many number combinations for 9 digits?

999,999,999 if you don't include 000000000, otherwise 1,000,000,000. If you don't allow repeated digits then 9 factorial, ie 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 = 362,880.

How many 5 digit combination are there 0-9?

infinite. not kidding. * * * * * Not kidding but NOT CORRECT either! There are 10!/(5!*5!) combinations where n! = 1*2* ... *n 10*9*8*7*6/(5*4*3*2*1) = 252 combinations.

How many 3 digit combinations can be made with 4 digits?

nCr = n!/r!(n-r)! = 4 I'm using the combination formula where the place of the digits is not important No if the place for instance the combination 312 is the same as 213. But I think you are asking for a permutation instead where the placements of the digits are also important. So it would (MORE)

How many 3 digit combinations can be made from 1 to 9?

All the numbers from 0 to 999 so 1000 numbers However if you mean only using each number once the answer is about 720 * * * * * No. The above answer refers to the number of permutations. Permutations are NOT the same as combinations as anyone who has studies any probability theory can tell y (MORE)

How many number combinations for 9 digits repeat allowed?

More then 30 how do i know that because i did it it took me more then 3 hours * * * * * Given that in a combination, 123124125 is the same as 111222345 or 321521421 etc (the order does not matter), I make the answer 8,697,700 - anyone willing to check? This is much smaller than the 900,000,0 (MORE)

How many combinations are there in a 9 digit number?

Does order matter? A common mistake is saying "combinations" when you actually mean "permutations". In the topic of Probability, permutations are ordered , while combinations are unordered . This means that for permutations, "123456789" and "987654321" are each considered unique results. W (MORE)

How many 3 digit combinations there 0-9?

The order of the digits in a combination does not matter. So 123 is the same as 132 or 312 etc. There are 10 combinations using just one of the digits (3 times). There are 90 combinations using 2 digits (1 once and 1 twice). There are 120 combinations using three different digit. 220 in all.

How combination in a 9 digit number?

There are different numbers of combinations for groups of different sizes out of 9: 1 combination of 9 digits 9 combinations of 1 digit and of 8 digits 36 combinations of 2 digits and of 7 digits 84 combinations of 3 digits and of 6 digits 126 combinations of 4 digits and of 5 digits 2 (MORE)

How many four digit numbers can be made using the digits 4 3 0 and 9 without repeating the digits?

The general rule is to imagine that you have four places in the number eg 9999 then calculate by saying 4 x 3 x 2 x 1 = 24. That gives you: 24 altogether if you allow numbers starting with ZERO. 18 otherwise. SIX starting with 0: 0349 0394 0439 0493 0934 0943 SIX starting with 3: (MORE)

How many 3 digit combinations can be made from 0 to 6 digits?

I'll assume that you mean " ... from the digits 0, 1, 2, 3, 4, 5,and 6 ?" . -- If the same digit can appear more than once in the samecombination, then there are (7 x 7 x 7) = 343 possibilities. -- If the three digits in one combination must all be differentdigits, then there are (7 x 6 x 5) = 210 (MORE)