0 2 3 6 7 1 sequence?

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Here is a rule (which works in English, but perhaps in no other language) to recover the desired sequence: 0=zero, 1=one, 2=two, 3=three, 4=four, 5=five, 6=six, 7=seven, 8=eight, 9=nine. Now rearrange in inverse alphabetical order: zero=0, two=2, three=3, six=6, seven=7, one=1, nine=9, four=4, five=5, eight=8.

You can also use an interpolating polynomial, which summarises the values in a single formula. If x takes on values from 1 to 6, the sequence can be recovered with:
((((6x-119)x+801)x-2194)x+2280)(x-1)/120

There may be better ways to generate the 6 numbers.
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Which number is the next logical number in the sequence 4 3 6 3 2 7 2 1 8 1?

0. The next logical number in this series would be 0. The number after that would be 9 followed by another 0. The pattern can be understood as pairs that add up to nine. 3 and 6 add up to 9. 2 and 7 add up to 9. 1 and 8 add up to 9. Each large number is 'cushioned' by two of its smaller (MORE)

What number completes the sequence 1 2 4 3 6 8 7 14 16?

The sequence doubles for the first one, then adds two for the next number, then subtracts one for the third, then repeats. So the next number is 15. 15. It's a three step operation : x 2, + 2, -1, The step after 16 is -1 which gives 15.

What is the mode of 0 1 2 3 4 5 6 7?

There isn't one. The mode is the most frequently occurring number, and seeing as each number listed in the question only appears once, there is no mode.

What is the sequence 0 2 3 6 7 1?

Here is a rule (which works in English, but perhaps in no other language) to recover the desired sequence: 0=zero, 1=one, 2=two, 3=three, 4=four, 5=five, 6=six, 7=seven, 8=eight, 9=nine. Now rearrange in inverse alphabetical order: zero=0, two=2, three=3, six=6, seven=7, one=1, nine=9, four=4, five= (MORE)

Using any maths Symbols or Signs prove it... 0 0 0 equals 6 1 1 1 equals 6 2 2 2 equals 6 3 3 3 equals 6 4 4 4 equals 6 5 5 5 equals 6 6 6 6 equals 6 7 7 7 equals 6 8 8 8 equals 6 9 9 9 equals 6?

the first one is: (0!+0!+0!)!=6 Because 0!=1 0!+0!+0!=3 and 3!=6 Just use factorial (1+1+1)! = 6 3 Factorial = 6 2+2+2 = 6 So Simple (3*3)-3 = 6 Also Simple Sqrt(4) + Sqrt(4)+ Sqrt(4) = 6 Sqrt(4) = 2 So 2+2+2 =6 5+(5/5) = 6 So Simple 6+6-6 = 6 Its quite simple 7-(7/7) = 6 Cuberoot(8) + (MORE)

Next number in sequence 1 2 4 3 6 8 7 14 16?

This is a 4 step sequence , starting with the number 1. 1) Double the number 2) Add 2 3) Subtract 1 4) Return to step 1) and repeat. 1 x 2 = 2 ; 2 + 2 = 4 ; 4 - 1 = 3 ; ..........7 x 2 = 14 ; 14 + 2 = 16. Then the next number is generated by Step 3).. 16 - 1 = 15

What comes next in this sequence 1 2 0 3 -1?

It seems that the numbers go farther and farther from a central point, one at a time, so the sequence would be 1, 2, 0, 3, -1, 4, -2, 5, -3, 6, etc. (The terms in odd positions go down one at a time, the terms in even positions go up one at a time.)

What does these numbers have in sequence 1 2 4 3 6 8 7 14 16?

It's a four step sequence. 1 is called the initial/start or seed number. Start with 1 .................................................... Step 1 : Double the previous number Step 2 : Add 2 Step 3 : Subtract 1 Step 4 : Return to Step 1 16 occurs after Step 2 so it is followed by 15,30,32,31,62,64. (MORE)

What is the number divided by 2 3 4 5 6 gives reminder 1 and remainder 0 if it divided by 7?

The numbers divided by 5 gives 1 remainder means it should endeither 1 or 6. But in case of number ends with 6 will be divided by2. So only number ending with 1 have to consider. Also the numbershould be divisble by 7. So when number ending with 3 is multipliedby 7 will give result of number ending (MORE)

Is there a program to define the best four number sequence for 1 2 3 4 5 6 7 8?

There are [ 8! = 40,320 ] ways to line up those 8 digits. If you go through all of those, you'll find that each and every 4-digit sequence appears 8,400 times. So it doesn't matter what you call the "best" one. Every possible one turns up the same number of times. On the other hand, if yo (MORE)

What are the next numbers after 0 2 3 6 7 1?

This sequence is all the single digits, written in reverse alphabetical order. The first value is 0, and zero comes last alphabetically. The next value is 2, and two comes second last alphabetically, and so on. From this, it is clear that the next few numbers will be 9,4,5 and 8 (eight being the f (MORE)

What is the next number in the sequence 2 3 6 7 1?

It can be any number you like. Given any number, it is alwayspossible to find a polynomial of degree 5 that will fit the abovenumbers and the give sixth number. The only polynomial of order 4is U n =(-n 4 - 6n 3 + 85n 2 -174n + 144)/24 for n = 1, 2, 3, ... This gives the next term as -18.

What number comes next in the sequence 3 7 1 0 1?

Given any number, it iis possible to find apolynomial of degree 5 that will fit the above points and theadditional point. Consequently, a rule can be found that canjustify any number as the "next". The only polynomial of order 4 is U n = (-3n 4 + 40n 3 -185n 2 + 336n - 176)/4 for n = 1, 2, 3, (MORE)

What is the nth term in this sequence 0 0 1 3 6 10?

There are infinitely many possible functions that can generate this sequence. One such is U n = (n 2 - 3n + 2)/2 = (n-2)*(n-1)/2 There are infinitely many possible functions that can generate this sequence. One such is U n = (n 2 - 3n + 2)/2 = (n-2)*(n-1)/2 There are infinitely many poss (MORE)

What is 8 5 4 9 1 7 6 10 3 2 0?

They are the numbers 0 to 10 in the alphabetic order of their names in the English language. Totally irrelevant to millions who don't count in English.

What is the next number in the sequence 1 2 0 3 -1?

Any number can be the next number. It is easy to find a rule based on a polynomial of order 5 such that the first five numbers are as listed in the question followed by the chosen next number. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, t (MORE)

What comes next after 0 2 3 6 7 1?

Any number that you choose can be the next number. It is easy to find a rule based on a polynomial of order 6 such that the first six numbers are as listed in the question followed by the chosen next number. There are also non-polynomial solutions. Short of reading the mind of the person who posed (MORE)