# What are the intercepts of 2x plus 6y 12?

# What is the y-intercept of -2x 2y x 12?

The equation -2x=2y*12 is first simplified to y = ((-2x)/12)/2 y = -2x/24 y = -x/12 The graph is then graphed and the equation intersects the y-axis at y = 0. So the y-intercept is 0.

# What is the y intercept and the x intercept to 2x plus 4y equals 8?

2X + 4Y = 8.
The Y-intercept is the place where the line described by the equation crosses the.
Y-axis. But X=0 everywhere on the Y-axis. So at that point, 4Y = 8, and Y = 2..
The X-intercept is the place where the line described by the equation crosses the.
X-axis. But Y=0 everywhere on the X-a…xis. So at that point, 2X = 8, and X = 4. (MORE)

# What is the y-intercept of y equals 2X plus 5?

y = 2x + 5 At the y-intercept, x=0. y = 0 + 5 y = 5

# In 2x plus 6y equals 32 what is x?

2x plus 6y equals 32.
32 divided by 6= 5 R2.
5+2= 7x6= 42-5=37-2=35.
so X=5

# Y equals 2 2x plus 6y equals 22?

Since y = 2, 2x + 6y is the same as 2x + 12.\nBecause 2x + 12 = 22, 2x = 10.\nIf 2 Xes are equal to ten, then 1 X is equal to 5.

# What is X and y intercept of -2x plus 3?

if: y = -2x + 3 then: if y = 0: 0 = -2x + 3 2x = 3 x = 3/2 if x = 0: y = -2(0) + 3 y = 3 So the x-intercept is at {0, 3}, and the y-intercept is at {3/2, 0}

# X - 3y equals -3 and -2x plus 6y equals 12 solution?

x - 3y = -3: multiply by -2 giving -2x + 6y = 6, but -2x + 6y = 12 so we have a problem! Misprint?

# Given 2x plus y equals 12 find the x-intercept?

At the x-intercept, y = 0 So, from the equation, 2x + 0 = 12 or x = 6 So the x-intercept is (6,0)

# Graph equation 2x plus 6y equals 6?

2x + 6y = 6 Subtract 2x from each side: 6y = -2x + 6 Divide each side by 6: y = -1/3 x + 1 The graph is a straight line, with a slope of [ -1/3 ], and intersecting the y-axis at the point [ y = 1 ].

# What is the x-intercept of 3x plus 6y equals 12?

3x + 6y = 12â´ x + 2y = 4 â´ x = 4 - 2y if x = 0, then: 0 = 4 - 2y â´ 2y = 4 â´ y = 2 So the x intercept for that line is at point (0, 2)

# Solve by substitution method 2x plus 6y equals -10 and-2x plus y equals 17?

y = 17 + 2x from second equation, substitute in first equation: 2x + 6(17 + 2x) = -10 ie 2x + 102 + 12x = -10 ie 14x = -112 so x= -8 and -16 + 6y = -10 ie 6y = -10 +16 so y = 1 Other method: Add the two equations, giving 7y = 7 so y =1 and x = -8

# How do you turn 3x-6y equals 12 in slope intercept form?

3x-6y=12; subtract 12 & add 6y to both sides 3x-12=6y; divide by 6 (1/2)x-2=y; re-write y=(1/2)x-2 slope intercept form

# What is the x-intercept of the line 2x-6y plus 24 equals 0?

The x- intercept of a line occurs when the line crosses the x axis. When this happens the corresponding y value of this point will be 0. From this we know that x-intercepts have y = 0. To find the x-intercept of a line we can plug this y value into the formula and get a corresponding x. 2x - 6y +… 24 = 0 2x - 6(0) + 24 = 0 (substituting 0 for y) 2x + 24 = 0 (-6 * 0 is 0) 2x = -24 (add 24 to both sides) x = -12 (divide both sides by 2) The x-intercept of 2x - 6y + 2 = 0 is x = -12 & y = 0 or (-12, 0) (MORE)

# What are the x and y intercepts of -2x-6y equals 6?

-2x-6y=6 can be written as -6y=2x+6 or y=-2/6x-1 This tells us the y intercept is 1. You can also plug in x=0 to find the y intercept. So when you replace x with 0 in -2x-6y=6 you have -6y=6 so y=-1 again Now to find the x intercept, let y be 0 so 0=2x+6 or -6=2x which tells us x=-6/2 or -3 an…d this is the y intercept. (MORE)

# What are the intercepts of -4x plus 6y-5z equals 60?

-4x + 6y - 5z = 60 At the x-intercept , 'y' and 'z' are zero: -4x = 60 > x = -15 At the y-intercept , 'x' and 'z' are zero: 6y = 60 > y = 10 At the z-intercept , 'x' and 'y' are zero: -5z = 60 ===> z = -12

# Find the coordinates of the x and y intercepts of -5x plus 6y equals 30?

-5x + 6y = 30 At the x-intercept, y=0: -5x = 30 > x = -6 At the y-intercept, x=0: 6y = 30 > y = 5

# -2x plus 6y equals -16 what does x equal?

This can not be answered since there is only one equation with two unknowns(x,y). Unless it needs to be solved for the x-intercept: -2x+6y=-16 -2x = -6y-16 x=3y+8 Substitute 0 for y to get the x-intercept: x=8

# What is the x-intercept of 2x-3y equals 12?

you just put 0 in for Y and solve for x. So 2x-3(0)=12, so x=6.

# What is the x-intercept of y equals 2x plus 5?

The x intercept is where y = 0 y = 2x +5 = 0 2x + 5 = 0 2x = -5 x = -5/2 = -2.5

# What is the slope intercept form of 15x plus 6y equals 45?

15x + 6y = 45 6y = -15x + 45 (move y to left-hand side) y = (-15/6)x + 45/6 (divide by coefficient of y, 6) y = (-5/2)x + 15/2 (reduce fractions) This is your final answer. your slope is -5/2 and your intercept is 15/2.

# What is the y-intercept of y equals 2x plus 10?

The y-intercept means... When does the line cross through the y-axis? This happens when the x-value is zero... so simply just plug in zero for "x" y = 2 * (0) + 10 y = 10 y-intercept is equal to 10 For the x-intercept just make the y-value equal to zero.

# What is the slope intercept form of -2x-6y equals -8?

-2x - 6y = -8 2x + 6y = 8 6y = -2x + 8 y = -2/6 x + 8/6 y = -1/3 x + 4/3

# Is 2x plus 3y equals 12 parallel to 6y minus 4x equals 2?

Let's see. 2X + 3Y = 12 3Y = - 2X + 12 Y = -2/3X + 4 ---------------- 6Y - 4X = 2 6Y = 4X + 2 Y = 2/3X + 1/3 --------------------- Nope. They can't be. Plot a few points and see.

# What is the x intercept of 4x - 6y equals 12?

In order to find the x-intercept to a function, y must equal 0. First, set up the equation in terms of y So: 4x - 6y = 12 4x = 6y + 12 x = (6y)/4 + (12)/4 x = (6y)/4 + 3 Substitute 0 for y: x = (6[0])/4 + 3 x = (0)/4 +3 x = (0) + 3 x = 3 The x-intercept of 4x - 6y = 12 is (3,0)

# Solve this polyinomal 5x plus 6y plus 3y-2x?

5x + 6y + 3y - 2x you have to add like terms. add the y terms and then the x terms 9y + 3x this is your answer

# 3x plus 6y equals 18 2x plus 5y equals 20?

You need to be more clear about your question. 3x + 6y = 18 2x + 5y = 20 The two equations you give represent lines. I assume you're trying to find the point at which they intersect. There are various ways to work this out. One technique is to multiply each equation by a factor that gives …one of the two variables the same coefficient. For example, if we multiply the first equation by 2, and the second equation by 3, we get: 6x + 12y = 36 6x + 15y = 60 Then we can subtract one from the other, which gives us a solution for y: [6x + 12y = 36] - [6x + 15y = 60] _______________ [0x - 3y = -24] So -3y = -24, telling us that at the point of intersection, y = 8. We can then plug that back into one of the original equations and solve for x: 2x + 5y = 20 2x + 5(8) = 20 2x = 20 - 40 2x = -20 x = -10 So the lines intersect at the point (-10, 8). Another way to work it out is to solve one of the equations for a single variable, and then plug it into the other one: 3x + 6y = 18 â´ x + 2y = 6 â´ x = 6 - 2y 2x + 5y = 20 â´ 2(6 - 2y) + 5y = 20 â´ 12 - 4y + 5y = 20 â´ y = 20 - 12 â´ y = 8 That gives us the value 8 for y, which we can once again plug in to either of the original equations to find x: 2x + 5y = 20 â´ 2x + 40 = 20 â´ 2x = -20 â´ x = -10 Once again telling us that the lines intersect at the point (-10, 8) (MORE)

# What is the x intercept of a line whose equation is 5x plus 6y equals 15?

For the x intercept, put y = 0 in the equation. So 5x = 15 ie x = 3 So the intercept is (3,0)

# How many solutions exist for the system of equation x plus 6y equals 12 plus 2x plus 12y equals 1?

zero solutions . If you plot these two lines, you will see that they are parallel and do not intersect.

# What are the intercepts for the line -2x plus y equals 5?

The y intercept is where x = 0 and the x intercept is where y = 0. Choosing a value of 0 for x in the given equation yields y = 5 for the y intercept; choosing a value of 0 for y in the given equation yields -2x = 5 or x = -5/2 for the x intercept.

# How do you answer 2x plus 6y equals 32 and 5x-2y equals 12 using subtitution?

First, change 2x+6y=32 to x+3y=16. Then solve for x, which is x=-3y+16. Then substitute -3y+16 as x into 5x-2y=12 and solve for y. 5(-3y+16)-2y=12 -15y+80-2y=12 -17y+80=12 -17y=-68 y=4 Then substitute 4 as y in either equation to solve for x. 5x-2(4)=12 5x-8=12 5x=20 x=4 The answer is x=4 and y=4, o…r (4,4) (MORE)

# How do you find the y intercept of p of x equals x to the fourth plus 2x cubed plus x squared plus 8x minus 12?

p(x) = x 4 + 2x 3 + x 2 + 8x - 12 When you go to graph this function, you make 'y' = p(x) . At the y-intercept, 'x' is zero. There, y = -12 .

# What is the x intercept for -2x plus 2y equals 4?

Put in function form. - 2X + 2Y = 4 2Y = 2X + 4 Y = X + 2 -------------set to 0 X + 2 = 0 X = -2 --------------X intercept

# What is 6x plus 3y plus 6y-2x?

6x + 3y + 6y - 2x = (6x - 2x) + (3y + 6y) = 4x + 9y

# What is the order pair for 2x plus 6y equals 24?

There are infinitely many ordered pairs. The coordinates of each of the infinite number of points on the straight line defined by 2x + 6y = 24 (or equivalently, 3y = -x + 12) is an ordered pair that satisfies the requirements.

# What is the y intercept of 2x plus 6y equals 36?

A line intercepts the y axis when x=0. If we put x=0 into the equation we get 2x0 + 6y = 36 6y = 36 y = 6 (dividing both sides by 6) Thus the line intercepts the y axis when x is 0 and y is 6. This is the point with the coordinates (0,6)

# What is intercepts of 4x plus 3y equals 6y?

4x + 3y = 6y 4x = 3y 4 / 3 x = y The slope is 4 / 3 and the y intercept is 0.

# What is the y and x intercept for the equation 2x plus 3y equals 12?

2 x + 3 y = 12 For the y -intercept, x =0: 2(0) + 3 y = 12 3 y = 12 y = 4 Therefore, the y -intercept is at y =4, or (0,4) .
For the x -intercept, y =0: 2 x + 3(0) = 12 2 x = 12 x = 6 Therefore, the x -intercept is at x =46, or (6,0) .

# What is 2x-6y equals 9 in slope- intercept form?

2x-6y = 9 Rearranging: 6y = 2x - 9 Divide through by 6: y = (1/3)x - 3/2

# What is the x-intercept of 2x plus 8y equals 40?

This form needed. Y = mX + c 2X + 8Y = 40 8Y = - 2X + 40 Y = - 1/4 + 5 -----------------------zero out the Y - 1/4X + 5 = 0 - 1/4X = - 5 X = 20 -------------------your X intercept

# What is the slope of y intercept of the graph of 3x plus 6y equals 12?

The y-intercept of the line 3x + 6y =12 is ( 0, 2 ) The slope of the line 3x + 6y = 12 is -1/2 Firstly, let's find the y intercept. At the y intercept, the value of the x coordinate equals 0. Therefore, our equation would be: 3*0 + 6y = 12 0 + 6y = 12 6y = 12 We divide both sides by 6 and.. y = …2 We already know that x has to be 0, so the y intercept is at the point ( 0, 2 ) The slope can be found either by changing the form of the equation to slope-intercept form, or by finding another point on the line, and using the slope formula. Because it's getting late, I'm going to do the latter. Easiest point to find will be the x-intercept. At that point, y = 0. (This will mean the math should be easy.) 3x + 6*0 = 12 3x = 12 x = 4. So we have a second point at ( 4, 0 ). And the earlier point at ( 0, 2 ). The slope formula is ( y 2 - y 1 ) / ( x 2 - x 1 ). In our case: ( 2 - 0 ) / ( 0 - 4 ) 2 / -4 Simplify -1/2 (MORE)

# How many values of x and y satisfy the equations 2x plus 6y equals 12 and 3x plus 9y equals 18?

2X + 6Y = 12 3X + 9Y = 18 try elimination - 3(2X + 6Y = 12) 2(3X + 9Y = 18) - 6X - 18Y = - 36 6X + 18Y = 36 === I will say this system is dependent and an infinite number of solutions can be found.

# What is 3x plus 6y equals 12 in slope-intercept form?

3x + 6y = 12 Rearranging terms: 6y = -3x + 12 Divide through by 6: y = - 1 / 2 *x + 2

# What is the x and y intercept of 2x plus 3y equals -12?

To find the y-intercept, plug 0 in for x: 3y = -12 y = -4 To find the x-intercept, plug 0 in for y:.
2x = -12 x = -6 The y-intercept is y = -4, and the x-intercept is x = -6..

# What ae x and y intercepts of 2x - 3y 12?

If we put 2x - 3y = 12 into y = mx + b format, you will get.. y = 2/3x - 4 Therefore the intercepts would be... y= -4 x= 6

# What is the x intercept of y equals 2x plus 3?

The x-interceptin is where the graph crosses the y-axis, which is where y equals 0: 0 = 2x + 3 2x = -3 x = -3/2 So the x intercept is as x = -3/2 (and y = 0).

# Who can answer algebra question for you -solving line equation y6-8-x-6 -2x plus 2-2 plus 2y -calculating slope and y-intercept 4 plus x4y plus 3 -6y-2-24-xshow the work?

Without the inclusion of an equality sign the expression can not be considered to be an equation.

# What is the slope of -x plus 6y 12?

The slope of -x plus 6y is equals to 12 is said to be (2 + 1/6x).

# What is the intercept of the line 2x-3y plus 50?

If you mean: 2x-3y = 50 then y = 2/3x-50/3 whereas the slope is 2/3 and the y intercept is -50/3

# What is the center and radius of a circle whose equation is 2x squared plus 2y squared plus 2x -6y -9 equals 0?

Equation: 2x^2 +2y^2 +2x -6y -9 = 0 Divide all terms by 2: x^2 +y^2 +x -3y -4.5 =0 Completing the squares: (x+1/2)^2 +(y-3/2)^2 -1/4 -9/4 -4.5 = 0 So: (x+1/2)^2 +(y -3/2)^2 = 7 Centre of circle: (-1/2, 3/2) Radius of the circle is the square root of 7

# What are the centre and radius of a circle whose equation is 2x squared plus 2y squared plus 2x -6y -9 equals 0?

Divide all terms by 2 and so: x^2 +y^2 +x -3y -4.5 = 0 Completing the squares for x and y: (x+1/2)^2 + (y-3/2)^2 -1/4 -9/4 -4.5 = 0 Therefore: (x+1/2)^2 + (y-3/2)^2 = 7 The centre of the circle is at (-1/2, 3/2) and its radius is the square root of 7