# What is the height of the telephone pole if shadow is 20 feet long and the angle of elevation from the groung if 70 degrees?

It is just short of 54.9 feet.

# Area of an arch of circle with a radius of 70 feet The angle of the arch is 20 degrees?

855.21 square feet. A circle with a radius 70 would be (pi)(radius squared) = (3.1416) (70) (70) = 15,393.8 square feet. With a 20 degree angle that is 20/360ths of a circle, …so multiply your circle area by 20 and divide by 360 = 855.21 square feet.

# How do you determine the height of a tower if it casts a shadow 156 ft long on level ground when the angle of elevation of the sun is 20 degrees?

I'm pretty sure that it equals 158 ft tall.I did 156 squared (24,336) plus 20 squared (400) and then subtracted the original amount of 156 and 20, I got 136. Then I added the …136 to my 24,736 and got 24,872. Finally I square rooted 24,872 and got 157.70 and rounded to 158. Hope that this helps you.

# A lamp pole casts a shadow 49 feet long when the angle of elevation of the sun is 44.8 degrees Find the height of the lamp pole?

A pole casting a shadow 49 feet long with an angle of elevation of the sun of 44.8 degrees is 50 feet tall. (47.98 rounded to two places) Tangent (theta) = opposite / adjac…ent Tangent (44.9) = X / 49 X = 47.98 This does not take into account the curvature of the earth, but the error in this example is inconsequential, specifically an elevation error of about 0.015 percent.

# The shadow of a vertical tower is 58 feet long when the angles of elevation of the sun is 36 degrees. what is the height of the tower to the nearest foot?

tan(36) = H/58 where H is the height of the tower. So H = 58*tan(36) = 42 feet.

# How do you find the angle of elevation from the tip of the shadow of a 12 foot flag pole to the top of the pole is 60 degrees?

is that the entire question because you already gave the angle, meaning you now have every angle for the triangle created by the pole and shadow

# At a certain time of day the angle of elevation of the sun is 30 degree A tree has a shadow that is 25 feet long Find the height of the tree to the nearest foot?

Tan60= 25/Height. Height = 25/Tan60 = 14.43

# What is the height of a tower if its shadow is 500 feet long and a flag pole is 40 feet tall with a shadow 36 feet long?

The ratio of the height of the object to its shadow are the same for both objects. So, if H is the height of the tower, then H/500 = 40/36 therefore H = 500*40/36 = 555.55...… feet.

# When the angle of elevation to the sun is 52 degrees a tree casts a shadow that is 9 meters long what is the height of the tree?

It is: tan(52)*9 = 11.519 meters rounded to three decimal places

# When the angle of elevation on of the sun is 75 degree a building casts shadow of 125 feet how tall is the degree?

If you mean the height of the building then it works out as 466.5063509 feet

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# The shadow of a telephone pole is 20 feet long. you can measure the angle of elevation from the end to the shadow to the top of the telephone pole to be 70. what is the height of the telephone pole Ro?

Height of telephone pole: 20*tan(70) = 55 feet rounded

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# What is the height of a flag pole whose shadow is 7.42 yards long when the angle of elevation towards the sun is 48.4 degrees?

Height of flag pole: tangent(48.4) times 7.42 = 8.36 yards rounded to two decimal places

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# What is the height of a flag pole that cast a shadow of 7.42 m at an angle of elevation 48.4 degrees on level ground?

Using tangent ratio for a right angle triangle: tan(48.4)*7.42 = 8.357 m which is the height of the flag pole rounded to 3 decimal places

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# What is the approximate height of a building when the angle of elevation at the top of a building is 34 degrees and at a point 80 feet closer the angle of elevation is 45 degrees?

It can be shown that: .
height = (d tan Î± tan Î²)/(tan Î± - tan Î²) where: .
Î± is the angle closest to the object .
Î² is the angle further away from the o…bject .
d is the distance from the point of angle Î± to the point ofangle Î² Thus: height = (80 ft Ã tan 45Â° Ã tan 34Â°)/(tan 45Â° - tan 34Â°) â 165.78ft

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# What is the height of a building if the angle of elevation to the top from a point on the ground is 31.4 degrees and from 53 feet further back it is 26.4 degrees?

It can be shown that: .
height = (d tan Î± tan Î²)/(tan Î± - tan Î²) where: .
Î± is the angle closest to the object .
Î² is the angle further away from the o…bject .
d is the distance from the point of angle Î± to the point ofangle Î² Thus: height = (53 ft Ã tan 31.4Â° Ã tan 26.4Â°)/(tan 31.4Â° - tan 26.4Â°) â140.87 ft