What is the purpose of writing a word equation in chemistry?
It is one way of representing a chemical reaction: it tells you what reacts and what is produced. Word equations are an efficient way to describe chemical changes, to help chemists recognize patterns, and to predict the products of a chemical reaction.
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p=8+14d-7 is the standard equation for biology
There is no point to chemistry.
When a chemical reaction occurs, it can be described by an equation. This shows the chemicals that react (called the reactants ) on the left-hand side, and the chemicals th…at they produce (called the products ) on the right-hand side. The chemicals can be represented by their names or by their chemical symbols. Unlike mathematical equations, the two sides are separated by an arrow, that indicates that the reactants form the products and not the other way round.
keisha Mr.Taylor 10/27/08 BJM . Equator-An equator is a invisible line across the earth and it's very very hot when you get close to it. . Compass- An compass is a magnet th…at points the diretions you want to go. . Island-An island is a keisha Mr.Taylor 10/27/08 BJM . Equator-An equator is a invisible line across the earth and it's very very hot when you get close to it. . Compass- An compass is a magnet that points the diretions you want to go. . Island-An island is a Sentence: the equator is so far from here
Writing a chemical (symbol) equation from a word equation? You'll have to identify the elements and compounds in the equation and snag the correct chemical symbols for each el…ement and each compound. This might present a bit of a challenge, paticularly if there is a "hydroxide" or a "chlorate" or an "oxalate" or something like that. In that case, you'll have to look up that anion or cation and see what elements make it up. Then you'll have to write up each reactant paying attention to insure you have the right proportions set down for your individual materials. Shall we do a few examples?. If you have oxygen you know that oxygen doesn't hang around by itself. I has a buddy, and is O 2 in equations. Note that the subscript 2 is applied to tell us there are two atoms of oxygen in the diatomic molecule of this element. Simple. But, if you have sodium hydroxide, you'll know sodium in this compound is Na + and the hydroxide isn't an element but and ion written as OH - in our expressions. It's oxygen and hydrogen (combined) with a -1 charge. Further, you'll have to account for the fact that Na and OH combine in a one-to-one ratio, and NaOH is sodium hydroxide. In contrast, if you are given calcium hydroxide, Ca and OH combine in a one-to-two ratio, and Ca(OH) 2 is the way we write this compound. It can get hairy, and you'll have to do some digging to insure you have the ions correctly written and the combination of elements set correctly in the expression of a compound. Once you've stepped through that, you can set up your equation.. Certainly you'll have to know which materials are on the one side of the equation and which ones are on the other. So now you've got the chemical expressions, and they're divided up into "left side" and "right side" groups. It's time to balance the equation. This may look daunting, but it's just a numbers game. It isn't totally dissimiliar from finding lowest common multiples for a group of numbers. Let's look at some examples.. In the simple (classic!) acid-base reaction, an acid and a base react to yield a salt and water. We'll use sodium hydroxide and hydrochloric acid mix them up to yield sodium chloride (table salt) and water. Sodium hydroxide is NaOH and hydrochloric acid is HCl. Let's hook them up and get the salt and water.. Sodium hydroxide plus hydrochloric acid yields sodium chloride and water.. NaOH + HCl => NaCl + H 2 O. We're not done. We've got our compounds correctly expressed throughout all the equation, and now we need to move on to balance the equation. We must insure everything on one side appears over on the second side. Each atom must be accounted for, every single one. So let's do that. There is one Na on each side. There is one O on each side. There are 2 H's on each side, one each in the NaOH and the HCl, and 2 in the H 2 O on the other side. That checks. There is one Cl on each side, too. We're good. It's a balanced equation. We need to do one more. Here it is. Calcium hydroxide plus sulfuric acid yields calcium sulfate plus water.. Ca(OH) 2 + H 2 SO 4 => CaSO 4 + H 2 O. That's the correct expression of the materials, so let's move on to balance the equation. There is 1 Ca on each side. There is an SO 4 on each side, too. (We skipped to that ion, and treated it as a "whole" unit.) The problem we have is that there are 4 hydrogens on the left side - 2 in the (OH) 2 of the first compound, and 2 in H 2 of the second compound - and only 2 of the H units on the right side, where they appear in the H 2 O there. We need to balance this. We also have 2 atoms of O in the (OH) 2 on the left, and only 1 of the O atoms on the right in the H 2 O there. (Note that we treated the SO 4 as a unit, which we can do. In an acid-base reaction, we often "shortcut" the process by doing that. We also treat water as H plus OH to make balancing easier, as the H is contributed by the acid and the OH is contributed by the base.) Moving on to balance the equation, all we have to do is double the number of water molecules to solve our problem. That will raise the H and and the O atom count. Let's do that by writing a 2 in front of the water molecule and see how things look.. Ca(OH) 2 + H 2 SO 4 => CaSO 4 + 2H 2 O. Now we're cooking! There are 4 of the H atoms on the left and 4 on the right side. And there are now 2 of the O atoms on the left side (again, leaving the SO 4 ion intact on both sides of the equation) and 2 of the O atoms in the water on the right side. Piece of cake. And you can do this. You can always balance an equation. Things may get "fat" number wise, but it can always be balanced. Just be sure you've reduced the numbers to lowest multiples so you don't end up with something out of control.. The key to this is practice. If you're rolling up your sleeves to begin chemistry, take this stuff to the bank. This is all there is to it, but you need to actually work a number of equations to get it down. So start. And you'll also begin to learn the composition of the chemical ions (sometimes called radicals) like the hydroxide and the sulfate used as examples here. Easy as pie, and you can do this ! Just remember to come back and answer a few questions here to pass on the knowledge. Good luck with your studies (but understand that luck is no substitute for study).
You cannot use any special characters in the question, but you can use many special characters in the answers. By looking at the character map on your computer to see what cha…racters are available, you can try typing or copying and pasting them into the answer to see how well they post.
one example is zinc+iron sulphate= iron+ zinc sulphate
1. To make clear what happens in a chemical reaction.2. To account for the disposition of the elements in each compound involved in the reaction.
H2o + co2 ----> o2 + carbohydrate
Many people still equate mental illness to insanity, but they are not the same, and in fact, the majority of mentally ill people are not insane.
reactant + reactant -> reaction
12H 2 O (Water) + 6CO 2 (Carbon Dioxide) + Light Energy = 6O 2 (Carbon Dioxide) + 6H 2 O (Water) + C 6 H 12 O 6 (Glucose)
K+CL=KCL From the above reaction K=POTASSIUM CL =CHLORINE KCL= POTASSIUM CHLORIDE SORRY FOR NOT DISPLAYING THE THE CHARGE ON IONS
A word equation is one way of representing a chemical reaction. Word equations are a more efficient way to describe chemical changes and to predict the products of a chemical …reaction.
Equator-An equator is a invisible line across the earth and it's very very hot when you get close to it
It is reasonably simple. You first want to make each word which is relavent to find out the answer a letter. An example of this could be a common example in chemistry in which… you are given current and time. From this you would want to find the amount of charge or coloumbs, make charge a letter such as I and time one such as T. Using an Equation you can work out that Q (Charge)=IxT. So just times those two together and there you have your answer via using an equation.